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Ningbo 2011 / China, hard , www, LIVE, DRAW, ATP Ningbo 2011 Tenis live
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12.09.11
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sferturi de finala Statham Jose (NZL) [4 BYE] (605) 2 6 6 I H2H O
Xu Jun-Chao (CHN) [6 BYE] (793) 0 1 2
12.09.11
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sferturi de finala Gregorc Luka (SLO) [3 BYE] (465) 2 7 6 I H2H O
Ito Yuichi (JPN) [5 BYE] (698) 0 5 1
12.09.11
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sferturi de finala Yoo Daniel (KOS) [2 BYE] (462) 2 6 3 7 I H2H O
Kim Cheong-Eui (KOS) [7 BYE] (803) 1 4 6 6
12.09.11
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sferturi de finala Rungkat Christopher (IND) [1 BYE] (448) 2 6 5 6 I H2H O
Nam Ji Sung (KOS) (1123) 1 4 7 2
11.09.11
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optimi de finala Kim Cheong-Eui (KOS) [7 BYE] (803) 2 6 6 I H2H O
Lu Yang (CHN) (1893) 0 1 2
11.09.11
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optimi de finala Gregorc Luka (SLO) [3 BYE] (465) 2 6 6 I H2H O
Liu Siyu (CHN) [WC] 0 2 0
11.09.11
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optimi de finala Ito Yuichi (JPN) [5 BYE] (698) 2 6 6 I H2H O
Boe-Wiegaard William (USA) (1404) 0 3 2
11.09.11
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optimi de finala Statham Jose (NZL) [4 BYE] (605) 2 6 6 I H2H O
Yang Zi-Dong (CHN) (1614) 0 1 1
11.09.11
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optimi de finala Xu Jun-Chao (CHN) [6 BYE] (793) 2 6 7 I H2H O
Li Yi-Feng (CHN) (1404) 0 1 6
11.09.11
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optimi de finala Yoo Daniel (KOS) [2 BYE] (462) 2 6 6 I H2H O
Jeong Suk-Young (KOS) (880) 0 4 1
11.09.11
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optimi de finala Nam Ji Sung (KOS) (1123) 2 7 6 I H2H O
Sharan Divij (IND) [8 BYE] (811) 0 6 1
11.09.11
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optimi de finala Rungkat Christopher (IND) [1 BYE] (448) 2 6 4 7 I H2H O
Cho Soong-Jae (KOS) (1050) 1 2 6 5
10.09.11
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1. runda Nam Ji Sung (KOS) (1123) 2 7 2 6 I H2H O
Kibi Yuya (JPN) (1264) 1 6 6 3
10.09.11
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1. runda Jeong Suk-Young (KOS) (880) 2 6 6 I H2H O
Wang Ying-Zheng (CHN) 0 2 2
10.09.11
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1. runda Lu Yang (CHN) (1893) 2 7 6 I H2H O
Li Yu Cheng (CHN) (1775) 0 6 3
10.09.11
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1. runda Liu Siyu (CHN) [WC] 2 3 7 6 I H2H O
Qi Xiao (CHN) 1 6 6 4
10.09.11
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1. runda Boe-Wiegaard William (USA) (1404) 2 3 6 6 I H2H O
Li Zheng (CHN) 1 6 1 3
10.09.11
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1. runda Yang Zi-Dong (CHN) (1614) 2 7 7 I H2H O
Zhu De-Long (CHN) 0 5 6
10.09.11
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1. runda Li Yi-Feng (CHN) (1404) 2 6 6 I H2H O
Feng Nian (CHN) (1451) 0 2 4
10.09.11
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1. runda Cho Soong-Jae (KOS) (1050) 2 6 6 I H2H O
Xue Feng (CHN) 0 4 0
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