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Jankovits Yannick (1672) / Franta Stevenson Kelsey (1789) / Canada
Yannick Jankovits
castigate: 3
pierdute: 0
procentaj: 100 %
Kelsey Stevenson
castigate: 0
pierdute: 3
procentaj: 0 %
Jankovits Yannick (1672) / Franta vs. Stevenson Kelsey (1789) / Canada
Jun 20, 2017
06:00
1. runda Jankovits Yannick (Fra.) 2 6 6 1.1 Hua Hin hard I
Stevenson Kelsey (Kan.) 0 1 2 5.1
Dec 1, 2015
07:00
1. runda Jankovits Yannick (Fra.) [1] 2 6 6 1.04 Phnom Penh I hard I
Stevenson Kelsey (Kan.) [Q] 0 3 4 7.25
Nov 8, 2011
00:00
1. runda Jankovits Yannick (Fra.) 2 6 6 Phuket I acoperit I
Stevenson Kelsey (Kan.) 0 2 1